This TextFieldParser Class is located in Microsoft.VisualBasic.IO name space of the .Net Framework.

The below examples read the sample CSV file using VB.Net

Sample File :

"REVIEW_DATE","AUTHOR","ISBN","DISCOUNTED_PRICE"
"1985/01/21","Douglas Adams",0345391802,5.95
"1990/01/12","Douglas Hofstadter",0465026567,9.95
"1998/07/15","Timothy ""The Parser"" Campbell",0968411304,18.99
"1999/12/03","Richard Friedman",0060630353,5.95
"2001/09/19","Karen Armstrong",0345384563,9.95
"2002/06/23","David Jones",0198504691,9.95
"2002/06/23","Julian Jaynes",0618057072,12.50
"2003/09/30","Scott Adams",0740721909,4.95
"2004/10/04","Benjamin Radcliff",0804818088,4.95
"2004/10/04","Randel Helms",0879755725,4.50

Code:

Dim parser As New FileIO.TextFieldParser("D:\Tests.txt")
Dim rows As String()
parser.SetDelimiters(",")
parser.TextFieldType = FileIO.FieldType.Delimited
Try
'Try to read the file
'Read the Header data
rows = parser.ReadFields

'print the Header
For Each str As String In rows
Console.WriteLine(str)
Next

'Read the row data
Do While Not parser.EndOfData
rows = parser.ReadFields

'Print the Results
For Each Str As String In rows
Console.WriteLine(Str)
Next

Loop
Catch ex As FileIO.MalformedLineException
MessageBox.Show(ex.Message)

Catch ex As Exception
'Show the Error Message
MessageBox.Show(ex.Message)
End Try

This part of the code read only the header information( First line of Header file ) and

display them in the console window.

Code:

rows = parser.ReadFields
'print the Header
 For Each str As String In rows
  Console.WriteLine(str)
Next

Output:

REVIEW_DATE
AUTHOR
ISBN
DISCOUNTED_PRICE

This read the values by line by line,split them using “,” and display it in console window.

Code:

'Read the row data
Do While Not parser.EndOfData
rows = parser.ReadFields
'Print the Results
For Each Str As String In rows
        Console.WriteLine(Str)
      Next
Loop

Output:

1985/01/21
Douglas Adams
0345391802
5.95
1990/01/12
Douglas Hofstadter
0465026567
9.95
1998/07/15
Timothy "The Parser" Campbell
0968411304
18.99
1999/12/03
Richard Friedman
0060630353
5.95

Now what happens when the file is not in the proper format. This is handled by the exception module.

I used this text for parsing

Dim text = "I, Need, Coffee, Before, I, ""Fall, Asleep"" Otherwise, ""I'll, Die""" ',

and it gave the exception as

"Line 1 cannot be parsed using the current Delimiters."

If you still need the detailed explanation then you can use the MalformatedLineException Class

Catch ex As FileIO.MalformedLineException
MessageBox.Show(ex.Message)

If the source file does not exist then File not found exception will be thrown , this has to be handled